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(R)=8800R-110R^2
We move all terms to the left:
(R)-(8800R-110R^2)=0
We get rid of parentheses
110R^2-8800R+R=0
We add all the numbers together, and all the variables
110R^2-8799R=0
a = 110; b = -8799; c = 0;
Δ = b2-4ac
Δ = -87992-4·110·0
Δ = 77422401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{77422401}=8799$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8799)-8799}{2*110}=\frac{0}{220} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8799)+8799}{2*110}=\frac{17598}{220} =79+109/110 $
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